Question #86821
A rod of iron and a rod of zinc are each 2 meters long at 0 degree and both are heated equally. At 50 degrees centigrade the Zinc rod is found to be longer by 0.181cm. Find the linear expansivity of iron when that of zinc is 0.0000598 per k.
1
Expert's answer
2019-03-25T08:45:45-0400

i0=z0=l0=2 m;(z50i50)=0.181 cm=0.00181 m;αz=0.0000598 K1;Δt=50 K;(z50i50)=z0(1+αzΔt)i0(1+αiΔt);αi=αzz50i50l0Δt=0.0000598 K10.00181 m2 m  50 K0.0000417 K1.i_0 = z_0 = l_0 = 2~\text{m}; \\ (z_{50} - i_{50}) = 0.181~\text{cm} = 0.00181~\text{m}; \\ \alpha_z = 0.0000598~\text{K}^{-1}; \\ {\Delta}t = 50~\text{K}; \\ (z_{50} - i_{50}) = z_0(1+\alpha_z{\Delta}t) - i_0(1+\alpha_i{\Delta}t); \\ \alpha_i = \alpha_z - \frac{z_{50}-i_{50}}{l_0{\Delta}t} = 0.0000598~\text{K}^{-1} - \frac{0.00181~\text{m}}{2~\text{m}~*~50~\text{K}} \approx 0.0000417~\text{K}^{-1}.


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