"i_0 = z_0 = l_0 = 2~\\text{m}; \\\\\n(z_{50} - i_{50}) = 0.181~\\text{cm} = 0.00181~\\text{m}; \\\\\n\\alpha_z = 0.0000598~\\text{K}^{-1}; \\\\\n{\\Delta}t = 50~\\text{K}; \\\\\n(z_{50} - i_{50}) = z_0(1+\\alpha_z{\\Delta}t) - i_0(1+\\alpha_i{\\Delta}t); \\\\\n\\alpha_i = \\alpha_z - \\frac{z_{50}-i_{50}}{l_0{\\Delta}t} = \n0.0000598~\\text{K}^{-1} - \\frac{0.00181~\\text{m}}{2~\\text{m}~*~50~\\text{K}} \\approx 0.0000417~\\text{K}^{-1}."
Comments
Leave a comment