Question #8662

The ice and steam points on a thermometer correspond to X and 50mm respectively. A temperature of 60degree celcius corresponds to 52mm on the thermometer. Calculate the value of X

Expert's answer

Let:


T(60)=60CT(100)=100CT(x)=0CL(100)=50 mmL(60)=52 mmL(x)=?\begin{array}{l} T(60) = 60{}^{\circ} \mathrm{C} \\ T(100) = 100{}^{\circ} \mathrm{C} \\ T(x) = 0{}^{\circ} \mathrm{C} \\ L(100) = 50 \mathrm{~mm} \\ L(60) = 52 \mathrm{~mm} \\ L(x) = ? \\ \end{array}


Find how many mm on 1C1{}^{\circ}\mathrm{C}

L(1C)=L(100)L(60)T(100)T(60)=505210060=240=0.05 mmL(x)=L(100)L(1C)(T(100)T(x))=50(0.05100)=55 mm\begin{array}{l} L(1{}^{\circ} \mathrm{C}) = \frac{L(100) - L(60)}{T(100) - T(60)} = \frac{50 - 52}{100 - 60} = -\frac{2}{40} = -0.05 \mathrm{~mm} \\ L(x) = L(100) - L(1{}^{\circ} \mathrm{C}) * (T(100) - T(x)) = 50 - (-0.05 * 100) = 55 \mathrm{~mm} \\ \end{array}


Answer: the value of X is: 55 mm

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