W=∫v1v2 pdV
V1 = 3.0/p1 = 3.0/1.5 = 2 m3
V2 = 3.0/p2 = 3.0/7.5 = 0.4 m3
W=∫20.4 (3.0/V) dV=3×[lnV]20.4=3×(ln0.4-ln2)= -4.83 barr×m3
As 1 barr = 105 N/m2, then W = -4.83*105 (N/m2)*m3 = -4.83*105 Nm = -4.83*105 J = -483 kJ
Answer: -483 kJ
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