Let's assume that we have 1 mole of triatomic gas.
Therefore 3NA (Avogardo's Number) is present initially.
So, 0.5 moles has 1.5NA atoms.
Now, 1 part of 0.5 moles remains undissociated.
So. degree of dissociation = 0.5 x 6 = 3
The other 0.5 moles has 1.5NA which breaks into 3 atoms.
So, total number of atoms = 0.5NA
Now, degree of freedom for monoatomic gas = 3
So, degree of freedom for 0.5NA monoatomic particles = 1.5 x 0.5 = 0.75
Hence, total will be 3 + 0.75 = 3.75
which is the required answer.
(2) 3.75
Comments
Leave a comment