Answer to Question #82829 in Molecular Physics | Thermodynamics for Dwayne

Question

Calculate how many grams of ice at 0°C would be melted by 100 g of 100°C steam

Answer 1

Answer on Question #82829, Physics / Molecular Physics | Thermodynamics

Calculate how many grams of ice at 0°C would be melted by 100 g of 100°C steam

Solution

Freezing temperature of water: 0 degrees c

Boiling temperature of water: 100 degrees c

Latent heat of fusion of water: 333 kJ/kg

Latent heat of vaporization of water: 2260 kJ/kg

Specific heat of water: 4186 J/kgK

Specific heat of ice: 2220 J/kgK

Find amount of heat, that will be released when 100 g of 1000C steam is cooled to 00C

Q = Q1 + Q2

Q1 = mHvap =- 0.1 kg  2260 kJ/kg = -226 kJ

Q2 = cmT = 4186 J/ kg K  0.1 kg  (273.15 K – 373.15 K) = - 41860 J = -41.86 kJ

Q= -226 kJ +(- 41.86 kJ) = - 267.86 kJ

The amount of heat released by steam will be absorbed by definite mass of ice:

Qreleased = Qabsorbed

Q absorbed = miceHfus

We should take positive value of Qabsorbed, as Q is absorbed by ice:

267.86 kJ = - mice333 kJ/kg

mice = 0.804 kg = 804 g

Answer: 804 g