3.1. The total internal energy of the system calculated by the formula: U=3/2nRT, where n - amount of substance, mole; R - gas constant, R=8.31 J/(K×mol); T – temperature, K. In this case n=2 moles, T=20+273.15=293.15 K. Then: U=3/2×8.31×293.15×2=7308.23 J.
Answer: 7308.23 J.
3.2. Average kinetic energy per molecule calculated by formula: E=3/2 k_BT, where kB – Boltzmann’s constant, kB=1.38×10-23 J/K; T – temperature, K. Then: E=3/2×1.38×10-23×293.15=6.07×10-21 J.
Answer: 6.07×10-21 J.
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