Let: L=10 (cm)
α=2×10−5
t1=30∘C
t2=100∘C
At heating the plate linearly extends equally in two dimensions:
ΔS=ΔL2
Side of plate will increase to:
ΔL=L×α(t2−t1)
ΔL=10×2×10−5×(100−30)=0.014(cm)
Area of one face of the plate will increase to:
ΔS=0.0142=0.000196(cm2)