Answer to Question #80357 in Molecular Physics | Thermodynamics for Cade lanum

Question

A ball initially at rest rolls down a hill with an acceleration of 4.5 m/s^2
If it accelerates for 9 seconds, how far will it move?

Answer 1

S=v_0 t+(at^2)/2, v_0=0 → S=(at^2)/2=(4.5∙9^2)/2=182.25 m.