Answer to Question #75389 in Molecular Physics | Thermodynamics for Christina Frechette

Question

At what rate (W) is heat lost through a 2.25 m by 1.75 m glass window pane that is 0.500 cm thick when the inside temperature is 24.5 0C and the outside temperature -11.5 0C

Answer 1

Rate = k A ΔT / d
ΔT = 297.65 K – 262.15 = 34.85 K
The area, A = (2.25 m)(1.75 m) = 3.94 m2,
k = 0.78 W/m·K
Rate = 0.78 W/m·K x 3.94 m2 34.85 K / 0.005 m = 21420 W