Answer on Question 74849, Physics, Molecular Physics, Thermodynamics
Question:
Using the Laplace formula, calculate the velocity of sound for air. Given γ = 1.4 \gamma = 1.4 γ = 1.4 , ρ = 1.29 k g m − 3 \rho = 1.29\, kgm^{-3} ρ = 1.29 k g m − 3 and P = 1.01 ⋅ 1 0 5 N m − 2 P = 1.01 \cdot 10^{5}\, Nm^{-2} P = 1.01 ⋅ 1 0 5 N m − 2 .
Solution:
The velocity of sound for air can be found from the Laplace formula:
v = γ P ρ , v = \sqrt{\frac{\gamma P}{\rho}}, v = ρ γ P ,
here, γ \gamma γ is the adiabatic index, ρ \rho ρ is the density of air and P P P is the pressure.
Then, we get:
v = γ P ρ = 1.4 ⋅ 1.01 ⋅ 1 0 5 N m 2 1.29 k g m 3 = 331 m s . v = \sqrt{\frac{\gamma P}{\rho}} = \sqrt{\frac{1.4 \cdot 1.01 \cdot 10^{5} \, \frac{N}{m^{2}}}{1.29 \, \frac{kg}{m^{3}}}} = 331 \, \frac{m}{s}. v = ρ γ P = 1.29 m 3 k g 1.4 ⋅ 1.01 ⋅ 1 0 5 m 2 N = 331 s m .
Answer:
v = 331 m s . v = 331 \, \frac{m}{s}. v = 331 s m .
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