Question

Gas mixture containing8 mole of oxygen and 2 moles of argon at room temperature. What is the total internal energy?

Answer 1

Answer on Question #74739, Physics / Molecular Physics | Thermodynamics

Gas mixture containing 8 mole of oxygen and 2 moles of argon at room temperature. What is the total internal energy?

Solution:

$$U = \frac {n _ {1} f _ {1}}{2} R T + \frac {n _ {2} f _ {2}}{2} R T$$

f is the degrees of freedom

$f_{1}$ for a diatomic gas $= 5$

$f_{2}$ for a monoatomic gas $= 1$

Therefore,

$$U = \left(\frac {8 m o l \times 5}{2} + \frac {2 m o l \times 1}{2}\right) \times 8. 3 1 \frac {J}{K m o l} \times 2 9 1 K = 2. 4 1 8 k J = 2 1 R T$$

Answer: 2.418 kJ o 21 RT

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