Answer on Question #74039, Physics / Molecular Physics | Thermodynamics
Question. A brick is dropped from 100 m up. Find its impact velocity and air time.
Given. h = 100 m ; v 0 = 0 h = 100 \, m; v_0 = 0 h = 100 m ; v 0 = 0 .
Find. v , t − ? v, t - ? v , t − ?
Solution.
So
h = v 0 t + g t 2 2 → h = g t 2 2 → t = 2 h g = 2 ⋅ 100 9.81 = 4.52 s . h = v_0 t + \frac{g t^2}{2} \rightarrow h = \frac{g t^2}{2} \rightarrow t = \sqrt{\frac{2h}{g}} = \sqrt{\frac{2 \cdot 100}{9.81}} = 4.52 \, s. h = v 0 t + 2 g t 2 → h = 2 g t 2 → t = g 2 h = 9.81 2 ⋅ 100 = 4.52 s .
For velocity
v = v 0 + g t → v = g t = 9.81 ⋅ 4.52 = 44.34 m / s . v = v_0 + g t \rightarrow v = g t = 9.81 \cdot 4.52 = 44.34 \, m/s. v = v 0 + g t → v = g t = 9.81 ⋅ 4.52 = 44.34 m / s .
Answer. v = 44.34 m / s ; t = 4.52 s v = 44.34 \, m/s; t = 4.52 \, s v = 44.34 m / s ; t = 4.52 s .
Answer provided by https://www.AssignmentExpert.com