Question #73486
Dry steam at 100 0c is bubbled into 500g of water originally at 200c. What will be the temperature of the water after 30g of steam has condensed?
Expert's answer
mL+mc(T_s-T)=Mc(T-T_w )
30(2265)+30(4.18)(100-T)=500(4.18)(T-20)
T=55℃.
30(2265)+30(4.18)(100-T)=500(4.18)(T-20)
T=55℃.
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