Question #71691

A 80.0-kg student climbs up a tree. The gravitational potential energy of the student at this point is 2.00 x 10(3) J. How high is the student above ground?

Expert's answer

Answer on Question #71691 – Physics – Molecular Physics | Thermodynamics

A 80.0-kg student climbs up a tree. The gravitational potential energy of the student at this point is 2.00×10(3)2.00 \times 10(3) J. How high is the student above ground?

Solution. Let the potential energy be zero on the ground level. Then


mgh=Epoth=2.00×103J9.81ms280.0kg=2.55m.mgh = E_{pot} \rightarrow h = \frac{2.00 \times 10^{3}J}{9.81 \frac{m}{s^{2}} \cdot 80.0\,kg} = 2.55\,m.


Answer. 2.55m2.55\,m

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