Question

A 10-meter object is placed at a distance
of 175 meters in front of a lens whose
focal length is 50 meters. Which of the
following describes the image formed?

Answer 1

Answer on Question #70656, Physics / Molecular Physics | Thermodynamics

A 10-meter object is placed at a distance of 175 meters in front of a lens whose focal length is 50 meters. Which of the following describes the image formed?

**Solution:**

Using thin lens formula: $\frac{1}{s_1} + \frac{1}{s_2} = \frac{1}{f}$,

where $f$ – focal length, $s_1, s_2$ – distance from the object and image to the lens

So, $s_2 = \frac{fs_1}{s_1 - f}$ – distance to the image

Magnification: $M = \frac{s_2}{s_1} = \frac{h_{image}}{h_{object}} \rightarrow h_{image} = \frac{s_2 h_{object}}{s_1} = \frac{f * h_{object}}{s_1 - f} = 50 * \frac{10}{125} = 4 \, \text{m}$

**Answer:**

Image height: **4m**

Answer provided by https://www.AssignmentExpert.com