Question

In boyle's law,If I increase the temperature of the gas enclosed in a cylinder from 0°C to 25°C in graph between pressure and volume ,which one increase and which decrase

Answer 1

Answer on Question #69874 Physics / Molecular Physics | Thermodynamics

In boyle's law, If I increase the temperature of the gas enclosed in a cylinder from $0{}^{\circ}\mathrm{C}$ to $25{}^{\circ}\mathrm{C}$ in graph between pressure and volume, which one increase and which decrease?

Solution:

The mathematical equation for Boyle's law is:

$$P V = k.$$

Where $P$ is the pressure, $V$ denotes the volume of the gas and $k$ is a constant value that depend on the temperature of the system.

If the temperature of the gas enclosed in a cylinder will increase the product $PV$ would increase too.

There are many transitions from initial to final state that satisfy condition: $PV$ increase. For examples see transitions 1-2 (volume is constant, pressure increases), 1-3 (both volume and pressure increases), 1-4 (volume increases, pressure is constant).

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