Answer on Question #67288, Physics / Molecular Physics | Thermodynamics
At 0 degree celcius the pressure of the gas in constant volume gas thermometer is 30cm Hg. Calculate the temperature when the pressure of the gas is 50 cm of Hg
Find: T2−?
Given:
T1=273 K
P1=76 cm Hg30 cm Hg×1.013×105 Pa=0.4×105 PaP2=76 cm Hg50 cm Hg×1.013×105 Pa=0.67×105 Pa
Solution:
Gay-Lussac's Law:
T1P1=T2P2(1)Of(1)⇒T2=P1P2T1(2)Of(2)⇒T2=457 K(3)Of(3)⇒t2=+184 ∘C
Answer:
+184 ∘C(457 K)
Answer provided by https://www.AssignmentExpert.com