Question #67288

At 0 degree celcius the pressure of the gas in constant volume gas thermometer is 30cm Hg. Calculate the temperature when the pressure of the gas is 50 cm of Hg

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Answer on Question #67288, Physics / Molecular Physics | Thermodynamics

At 0 degree celcius the pressure of the gas in constant volume gas thermometer is 30cm Hg. Calculate the temperature when the pressure of the gas is 50 cm of Hg

Find: T2?T_{2} - ?

Given:

T1=273 KT_{1} = 273\ \text{K}

P1=30 cm Hg76 cm Hg×1.013×105 Pa=0.4×105 PaP_{1} = \frac{30\ \text{cm Hg}}{76\ \text{cm Hg}} \times 1.013 \times 10^{5}\ \text{Pa} = 0.4 \times 10^{5}\ \text{Pa}P2=50 cm Hg76 cm Hg×1.013×105 Pa=0.67×105 PaP_{2} = \frac{50\ \text{cm Hg}}{76\ \text{cm Hg}} \times 1.013 \times 10^{5}\ \text{Pa} = 0.67 \times 10^{5}\ \text{Pa}


Solution:

Gay-Lussac's Law:


P1T1=P2T2(1)\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}} \quad (1)Of(1)T2=P2P1T1(2)\text{Of} \quad (1) \Rightarrow T_{2} = \frac{P_{2}}{P_{1}} T_{1} \quad (2)Of(2)T2=457 K(3)\text{Of} \quad (2) \Rightarrow T_{2} = 457\ \text{K} \quad (3)Of(3)t2=+184 C\text{Of} \quad (3) \Rightarrow t_{2} = +184\ {}^{\circ}\text{C}


Answer:


+184 C(457 K)+184\ {}^{\circ}\text{C} \quad (457\ \text{K})


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