Question

The time period of a simple pendulum ,called 'second pendulum ' is 2 s .Calculate the length ,angular frequency And frequency of the pendulum.

Answer 1

Answer on Question #66934 - Physics / Molecular Physics -Thermodynamics

Question:

The time period of a simple pendulum, called 'second pendulum' is 2 s. Calculate the length, angular frequency and frequency of the pendulum.

Solution:

The time period of the simple pendulum can be calculated as $T = 2 * \pi \sqrt{\frac{L}{g}}$, and considering $g = 9.81 \, \text{m/s}$, length of the pendulum $L = g * \left( \frac{T}{2\pi} \right)^2 = 0.995 \, \text{m}$. Frequency is equal to $f = \frac{1}{T} = 0.5 \, \text{Hz}$ and the angular frequency $\omega = \frac{2\pi}{T} = \pi \frac{\text{rad}}{\text{s}}$.

Answer: Length of the pendulum $L = 0.995 \, \text{m}$. Frequency is equal to $f = 0.5 \, \text{Hz}$ and the angular frequency $\omega = \pi \frac{\text{rad}}{\text{s}}$.

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