Question #66801

Derive an expression for the work done by a gaseous system for an isothermal expansion of an ideal gas.

Expert's answer

Answer on Question #66801, Physics / Molecular Physics | Thermodynamics

Derive an expression for the work done by a gaseous system for an isothermal expansion of an ideal gas.

**Solution:**

The work done by a gaseous system for an isothermal expansion of an ideal gas:


W=0WdW=V1V2PdV=V1V2mMRTVdV=mMRTlnV2V1,W = \int_{0}^{W} dW = \int_{V_{1}}^{V_{2}} P dV = \int_{V_{1}}^{V_{2}} \frac{m}{M} \frac{RT}{V} dV = \frac{m}{M} RT \ln \frac{V_{2}}{V_{1}},


where PP is the press of gas, mm is the mass of gas, MM is the molar mass of gas, RR is the gas constant, TT is the absolute temperature of the gas, V1V_{1} is the initial volume of gas, V2V_{2} is the last volume of gas.

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