Question

The time period of a simple pendulum ,called 'second pendulum ' is 2 s .Calculate the length ,angular frequency And frequency of the pendulum ?

Answer 1

Answer on Question #66792, Physics / Mechanics | Relativity |

A sinusoidal wave is describing by $y(x, t) = 3.0 \sin(3.52t - 2.01x)$ cm where $x$ is the position along wave propagation. Determine the amplitude, wave number, wavelength, frequency & velocity of the waves.

Solution

Lets write a equation of a plane wave and compare it with our equation $y(x, t) = 3.0 \sin(3.52t - 2.01x)$.

$$y(x, t) = A \sin(\omega t - kx),$$

where A is a magnitude, k is a wave’s wave number, $\omega$ is a wave’s angular frequency.

Therefore the amplitude $A = 3.0$ cm, the wave number $k = 2.01$, the frequency $\nu = \omega / 2\pi = 0.56$. The wavelength $\lambda = 2\pi / k = 3.12$ and the velocity $V = \lambda \nu = 1.75$.

**Answer**: $A = 3.0$, $k = 2.01$, $\lambda = 3.12$, $\nu = 0.56$, $V = 1.75$.

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