Answer on Question #66753-Physics-Molecular Physics-Thermodynamics
A sonometer wire having cross sectional area 0.85×1/1000000m2 is stretched between two rigid supports 1.2my apart. A tension of 20N is applied at its free end. If the temperature is reduced by 12∘C , Calculate the field tension in the wire. Take coefficient of linear expansion & isothermal young's modulus to be 1.5×1/100000N/K & 2×100000000000N/my , respectively.
Solution
ΔF=−AγαΔTΔF=(0.85⋅10−6)(2⋅1011)(1.5⋅10−5)(12)=F′=F+ΔF=20+30.6=50.6N.
Answer: 50.6 N.
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