Question #66753

A sonometer wire having cross sectional area 0.85×1/1000000 m2 is stretched between two rigid supports 1.2 my apart .A tension of 20 N is applied at its free end .if the temperature is reduced by 12°C, Calculate the field tension in the wire .Take coefficient of linear expansion & isothermal young's modulus to be 1.5× 1/100000 1/K & 2 ×100000000000 N/my, respectively.
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Expert's answer

2017-03-29T11:11:07-0400

Answer on Question #66753-Physics-Molecular Physics-Thermodynamics

A sonometer wire having cross sectional area 0.85×1/1000000m20.85 \times 1/1000000 \, \text{m}^2 is stretched between two rigid supports 1.2my1.2 \, \text{my} apart. A tension of 20N20 \, \text{N} is applied at its free end. If the temperature is reduced by 12C12{}^{\circ} \text{C} , Calculate the field tension in the wire. Take coefficient of linear expansion & isothermal young's modulus to be 1.5×1/100000N/K1.5 \times 1/100000 \, \text{N} / \text{K} & 2×100000000000N/my2 \times 100000000000 \, \text{N} / \text{my} , respectively.

Solution

ΔF=AγαΔT\Delta F = - A \gamma \alpha \Delta TΔF=(0.85106)(21011)(1.5105)(12)=\Delta F = (0. 8 5 \cdot 1 0 ^ {- 6}) (2 \cdot 1 0 ^ {1 1}) (1. 5 \cdot 1 0 ^ {- 5}) (1 2) =F=F+ΔF=20+30.6=50.6N.F ^ {\prime} = F + \Delta F = 2 0 + 3 0. 6 = 5 0. 6 N.


Answer: 50.6 N.

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