Answer on question #65788, Physics / Molecular Physics — Thermodynamics
Question how much heat energy can be absorbed by 375 grams of lead to raise its temperature by 25 Celsius
Solution This heat is
Q=cleadmΔt=1600⋅0.375⋅25=15000 JQ=c_{lead}m\Delta t=1600\cdot 0.375\cdot 25=15000\,JQ=cleadmΔt=1600⋅0.375⋅25=15000J
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