Question #64477

2 moles of air when heated though 10 k expand by 1.66 x 10 power -3 under a constant pressure 10 power 5 newton per meter square. if cv = 20.81 jmole k then cp is

Expert's answer

Answer on Question #64477, Physics / Molecular Physics | Thermodynamics

2 moles of air when heated through 10k10\mathrm{k} expand by 1.66×101.66 \times 10 power -3 under a constant pressure 10 power 5 newton per meter square. if cv = 20.81 jmole k then cp is

Find: cp?c_{p} - ?

Given:

cv=20.81J/mol×Kc_{v} = 20.81 \, \text{J/mol} \times \text{K}

R=8.31J/mol×KR = 8.31 \, \text{J/mol} \times \text{K}

Solution:

Air is an ideal gas.

Mayer's formula:


cpcV=R(1)c_{p} - c_{V} = R \cdot (1)


where R is gas constant

Of (1) cp=cV+R(2)\Rightarrow c_{p} = c_{V} + R \cdot (2)

Of (2) cp=29.12J/mol×K\Rightarrow c_{p} = 29.12 \, \text{J/mol} \times \text{K}

Answer:

cp=29.12J/mol×Kc_{p} = 29.12 \, \text{J/mol} \times \text{K}

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