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Answer to Question #6184 in Molecular Physics | Thermodynamics for fatumata sherif
Question #6184
A kangaroo is capable of jumping to a height of 2.62 m. determine the takeoff speed of the kangaroo.
Expert's answer
Due to energy conservation law
Mgh=Mv2/2
where M-mass of kangaroo, v- take off speedHence v=sqrt(2gh)=sqrt(2*10*2.62)=7.2 m/s
Mgh=Mv2/2
where M-mass of kangaroo, v- take off speedHence v=sqrt(2gh)=sqrt(2*10*2.62)=7.2 m/s
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