Question

5 grams of ice at 0 degree Celsius is mixed with 10 grams of water at 50 degree Celsius. What is the resultant temperature ?

Answer 1

Answer on question #53231, Physics / Molecular Physics — Thermodynamics

Question 5 grams of ice at 0 degree Celsius is mixed with 10 grams of water at 50 degree Celsius. What is the resultant temperature ?

Solution The equation of heat conservation is

$m_{ice}C_{melting}+m_{ice}\theta c_{water}=m_{water}c_{water}(t_{0}-\theta)$

where $\theta$ is resulting temperature of mixture, $C_{melting}$ is specific heat of melting ice and $c_{water}$ is specific heat capacity of water and $t_{0}$ is initial temperature of water. Hence

$\theta=\frac{m_{water}c_{water}t_{0}-m_{ice}C_{melting}}{c_{water}(m_{ice}+m_{water})}$

$\theta\approx 7.1{}^{\circ}C,$

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