Question

A spray can at 250 PSI is at room temperature. What will its temperature be if it expands to 16.5 x the volume when released?

Answer 1

Answer on Question #52579-Physics-Molecular Physics-Thermodynamics

A spray can at 250 PSI is at room temperature. What will its temperature be if it expands to 16.5 x the volume when released?

Solution

$$\frac {P _ {1} V _ {1}}{T _ {1}} = \frac {P _ {2} V _ {2}}{T _ {2}}.$$

So,

$$T _ {2} = \frac {P _ {2} V _ {2}}{P _ {1} V _ {1}} T _ {1}.$$ $$T _ {2} = \frac {14.7\ PSI \cdot 16.5 \cdot V _ {1}}{250\ PSI \cdot V _ {1}} \cdot 294.15\ K = 285.38\ K = 54.01{}^{\circ}F = 12.23{}^{\circ}C.$$

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