Question

The mass of a bottle of pepsi is 719.8 gm . If the soda volume is 746.1 ml and the weight of the empty bottle is 1.8 N . Calculate the density of the pepsi in kg/m3 .

Answer 1

Answer on Question #46496-Physics-Molecular Physics-Thermodynamics

The mass of a bottle of Pepsi is $m = 719.8 \, \text{gm} = 0.7198 \, \text{kg}$ . If the soda volume is $V = 746.1 \, \text{ml} = 0.7461 \, \text{l} = 0.7461 \cdot 10^{-3} \, \text{m}^3$ and the weight of the empty bottle is $W = 1.8 \, \text{N}$ . Calculate the density of the Pepsi in $\frac{\text{kg}}{\text{m}^3}$ .

Solution

The mass of Pepsi is

$$m _ {\mathrm {P e p s i}} = \mathrm {m} - \mathrm {m} _ {\mathrm {b o t t l e}},$$

where $\mathfrak{m}_{\mathrm{bottle}} = \frac{W}{g}$ is the mass of the empty bottle.

The density of the Pepsi is

$$\rho = \frac {m _ {\mathrm {P e p s i}}}{V} = \frac {\mathrm {m} - \frac {W}{g}}{V} = \frac {0 . 7 1 9 8 k g - \frac {1 . 8 N}{9 . 8 \frac {m}{s ^ {2}}}}{0 . 7 4 6 1 \cdot 1 0 ^ {- 3} m ^ {3}} = 7 1 8. 6 \frac {k g}{m ^ {3}}.$$

Answer: 718.6 $\frac{kg}{m^3}$ .

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