Question #45008

A containers volume is reduced by 75% And the gas inside had an initial temperature of 10 degrees Celsius. What is the final temperature in degrees Celsius if it compressed polytropically with n= 1.45

Expert's answer

Answer on Question #45008 – Physics – Molecular Physics | Thermodynamics

Question.

A containers volume is reduced by 75% And the gas inside had an initial temperature of 10 degrees Celsius. What is the final temperature in degrees Celsius if it compressed polytropically with n= 1.45


V2=0.25V1V_2 = 0.25V_1T1=10C=283 KT_1 = 10{}^\circ\mathrm{C} = 283\ \mathrm{K}n=1.45n = 1.45T2=?T_2 = ?

Solution.

The polytropic equation:


PVn=constPV^n = const


But from the equation of ideal gas we know


PV=RTPVT=R=constP=constVTPV = RT \rightarrow \frac{PV}{T} = R = const \rightarrow P = \frac{const}{V} T


Therefore,


TVn1=constTV^{n-1} = const


In our case,


T1V1n1=T2V2n1=constT2=T1(V1V2)n1T_1 V_1^{n-1} = T_2 V_2^{n-1} = const \rightarrow T_2 = T_1 \left(\frac{V_1}{V_2}\right)^{n-1}


Calculate:


T2=28340.45=2831.866=528.1 K=255.1CT_2 = 283 \cdot 4^{0.45} = 283 \cdot 1.866 = 528.1\ \mathrm{K} = 255.1{}^\circ\mathrm{C}

Answer.

T2=T1(V1V2)n1=528.1 K=255.1CT_2 = T_1 \left(\frac{V_1}{V_2}\right)^{n-1} = 528.1\ \mathrm{K} = 255.1{}^\circ\mathrm{C}


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