Question

calculate the root mean square velocity for oxygen molecules at temperatures 30c

Answer 1

Answer on Question #43122-Physics-Molecular Physics-Thermodynamics

Calculate the root mean square velocity for oxygen molecules at temperatures 30c

Solution

Using $v_{rms} = \sqrt{\frac{3RT}{M}}$ , the molar mass of molecular oxygen is $M = 31.9998\frac{g}{mol}$ ; the molar gas constant has the value $R = 8.3143\frac{J}{molK}$ , and the temperature is $T = 303.15K$ . Since the joule is the $\frac{kgm^2}{s^2}$ , the molar mass must be expressed as $M = 0.0319998\frac{kg}{mol}$ . The root mean square velocity is then given by:

$$v _ {r m s} = \sqrt {\frac {3 \cdot 8 . 3 1 4 3 \cdot 3 0 3 . 1 5}{0 . 0 3 1 9 9 9 8}} = 4 8 6. 1 \frac {m}{s}.$$

Answer: 486.1 $\frac{m}{s}$ .

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