Question #42888

Q.1 and 2
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Expert's answer

Answer on Question #42888, Physics, Molecular Physics | Thermodynamics

Task:

1. A paramagnetic gas at temperature 27C27{}^{\circ}\mathrm{C} is placed in an external uniform H magnetic field of magnitude 1.5 T. If the atoms of the gas have magnetic dipole moment μ=2.0μB\mu = 2.0\mu_{B}, then the energy difference between parallel alignment and antiparallel alignment of the atom's magnetic dipole moment with the magnetic field is:

(a) 2.3×1022J2.3 \times 10^{-22} \, \mathrm{J}

(b) 5.6×1023J5.6 \times 10^{-23} \, \mathrm{J}

(c) 1.9×1024J1.9 \times 10^{-24} \, \mathrm{J}

(d) 1.6×1025J1.6 \times 10^{-25} \, \mathrm{J}

Solution:

θ1=0,θ2=180,μB=9.271024J/T.\theta_{1} = 0, \theta_{2} = 180{}^{\circ}, \mu_{B} = 9.27 \cdot 10^{-24} \, \mathrm{J} / \mathrm{T}.μH(cosθ1cosθ2)=2μH=4μB1.5=69.2710245.61023J.\mu H (\cos \theta_{1} - \cos \theta_{2}) = 2 \mu H = 4 \mu_{B} \cdot 1.5 = 6 \cdot 9.27 \cdot 10^{-24} \approx 5.6 \cdot 10^{-23} \, \mathrm{J}.

Answer: (b) $5.6 \times 10^{-23} \, \mathrm{J}$

2. A series RLC circuit has inductance L=12mHL = 12 \, \mathrm{mH}, capacitance C=1.2μFC = 1.2 \, \mu \mathrm{F}, and resistance R=12ΩR = 12 \, \Omega. At what time will the amplitude of the charge oscillations in the circuit be 10%10\% of its initial value?

(a) 2.0 ms

(b) 3.0 ms

(c) 4.0 ms

(d) 5.0 ms

Solution:

lnA0eβtA0eβ(t+Δt)=ln(1/0.1)=βΔt=2RLΔtΔt=ln(1/0.1)L2R2.0ms\ln \frac{A_{0} e^{-\beta t}}{A_{0} e^{-\beta (t + \Delta t)}} = \ln (1 / 0.1) = \beta \Delta t = \frac{2R}{L} \Delta t \Rightarrow \Delta t = \frac{\ln (1 / 0.1) L}{2R} \approx 2.0 \, \mathrm{ms}

Answer: (a) 2.0 ms

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