Question

What amount of heat is required to raise the temperature of 20 grams of water from 10°C to 30°C? The specific heat of water is 4.18 J/g°C.

Answer 1

Answer on Question #42480 – Physics – Molecular Physics | Thermodynamics

Question.

What amount of heat is required to raise the temperature of 20 grams of water from $10{}^{\circ}\mathrm{C}$ to $30{}^{\circ}\mathrm{C}$? The specific heat of water is $4.18\mathrm{J} / \mathrm{g}{}^{\circ}\mathrm{C}$.

Given:

$$m = 20\,g$$ $$T_1 = 10{}^{\circ}\mathrm{C}$$ $$T_2 = 30{}^{\circ}\mathrm{C}$$ $$c = 4.18\, \frac{J}{g \cdot {}{}^{\circ}\mathrm{C}}$$

Find:

$$Q = ?$$

Solution.

The known formula of transmission of heat for heating:

$$Q = c m (T_2 - T_1)$$

Calculate:

$$Q = 4.18 \cdot 20 \cdot 20 = 1672\,J$$

Answer.

$$Q = c m (T_2 - T_1) = 1672\,J$$

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