Question #37948

hen resting, a person has a metabolic rate of about 7.84 x 105 joules per hour. The person is submerged neck-deep into a tub containing 2.06 x 103 kg of water at 20.9 °C. If the heat from the person goes only into the water, find the water temperature in degrees Celsius after half an hour.

Expert's answer

Answer on Question #37948, Physics, Molecular Physics | Thermodynamics

Question:

When resting, a person has a metabolic rate of about 7.84×1057.84 \times 10^{5} joules per hour. The person is submerged neck-deep into a tub containing 2.06×103 kg2.06 \times 10^{3} \mathrm{~kg} of water at 20.9C20.9{}^{\circ} \mathrm{C}. If the heat from the person goes only into the water, find the water temperature in degrees Celsius after half an hour.

Answer:


Q=cm(T2T1)Q = c m (T _ {2} - T _ {1})


where mm is mass, T2T1T_{2} - T_{1} – change of temperature, QQ is amount of heat.

Therefore, final temperature equals:


T2=T1+QcmT _ {2} = T _ {1} + \frac {Q}{c m}


Amount of heat equals:


Q=7.84105Jh0.5h=3.92105JQ = 7.84 * 10^{5} \frac{J}{h} * 0.5 \, h = 3.92 * 10^{5} J


Finally:


T2=T1+Qcm=20.9+3.9210541832.06103=21.16CT _ {2} = T _ {1} + \frac {Q}{c m} = 20.9 + \frac {3.92 * 10^{5}}{4183 * 2.06 * 10^{3}} = 21.16 \, {}^\circ \mathrm{C}


Answer: 21.2C21.2{}^{\circ} \mathrm{C}

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