Question

Blood flows through a section of a horizontal artery that is partially blocked by a deposit along the artery wall. As a hemoglobin molecule moves from the narrow region into the wider region, its speed changes from v2 = 0.800 m/s to v1 = 0.411 m/s. What is the change in pressure, P1 - P2, that it experiences? The density of blood is 1060 kg/m3.

Answer 1

Answer on Question#37464, Physics, Other

Question:

Blood flows through a section of a horizontal artery that is partially blocked by a deposit along the artery wall. As a hemoglobin molecule moves from the narrow region into the wider region, its speed changes from v2 = 0.800 m/s to v1 = 0.411 m/s. What is the change in pressure, P1 - P2, that it experiences? The density of blood is 1060 kg/m3.

Answer:

Bernoulli's principle can be expressed as a mathematical equation:

$$\frac {v ^ {2}}{2} + g h + \frac {p}{\rho} = c o n s t$$

where $v$ is the blood streams speed, $g$ is the acceleration due to gravity,

$h$ is the height, $p$ is the pressure, and $\rho$ is the density of the blood.

In our case:

$$\frac {v _ {1} ^ {2}}{2} + \frac {p _ {1}}{\rho} = \frac {v _ {2} ^ {2}}{2} + \frac {p _ {2}}{\rho}$$ $$p _ {1} - p _ {2} = \frac {\rho}{2} (v _ {2} ^ {2} - v _ {1} ^ {2}) = \frac {1 0 6 0 \frac {k g}{m ^ {3}}}{2} (0. 8 ^ {2} - 0. 4 1 1 ^ {2}) \frac {m ^ {2}}{s ^ {2}} = 2 5 0 P a$$

Answer: 250 Pa