Question

A sample of a gas occupies 1425 mL at 22 °C and 410 mmHg. What volume (in mL) will it occupy at the same temperature and 690 mmHg?

Answer 1

Answer on Question#37334 – Chemistry – Other

The combined gas law states that

$$\frac {P V}{T} = \text{const}, \text{i.e.} \quad \frac {P _ {1} V _ {1}}{T _ {1}} = \frac {P _ {2} V _ {2}}{T _ {2}}$$

Hence

$$V _ {2} = \frac {P _ {1} V _ {1} T _ {2}}{P _ {2} T _ {1}}$$ $$T _ {1} = T _ {2}, \text{ so}$$ $$V _ {2} = \frac {P _ {1} V _ {1}}{P _ {2}}$$ $$V _ {1} = 1425 \text{ mL}$$ $$P _ {1} = 410 \text{ mmHg}$$ $$P _ {2} = 690 \text{ mmHg}$$ $$V _ {2} = \frac {410 \cdot 1425}{690} = 847 \text{ mL}$$

Answer: 847 mL