Question

Calculate the average translational kinetic energy of a nitrogen molecule at 27 degree celcius

Answer 1

QUESTION:

Calculate the average translational kinetic energy of a nitrogen molecule at 27 degree celcius

SOLUTION:

According to the kinetic theory of gases the average translation kinetic energy of a particle is

$$E _ {u} = \frac {3}{2} k T$$

Here $\mathrm{T} = 27 + 273 = 300\mathrm{K}$ and

$$E _ {u} = \frac {3}{2} \cdot 1.38 \cdot 10 ^ {- 23} \cdot 300 = 6.21 \cdot 10 ^ {- 21} \mathrm{J}$$

Answer

$$6.21 \cdot 10^{-23} \mathrm{J}$$