Question #36084

Hi! Could you please explain the solution to me step by step?

At a party some balloons are filled with helium. To fill them they have used gas from a bottle with volume 45 dm^3 and the pressure 1.00 MPa. The balloons are made to hold a pressure of 150 kPa. How many such balloons you can inflate if the balloons have an average volume of 4.0 dm^3?

Expert's answer

Question #36084

Hi! Could you please explain the solution to me step by step?

At a party some balloons are filled with helium. To fill them they have used gas from a bottle with volume 45 dm³ and the pressure 1.00 MPa. The balloons are made to hold a pressure of 150 kPa. How many such balloons you can inflate if the balloons have an average volume of 4.0 dm³?

Solution:

Let


Vbottle=45LV_{\text{bottle}} = 45 \, \text{L}Pbottle=1.00MPa=1000kPaP_{\text{bottle}} = 1.00 \, \text{MPa} = 1000 \, \text{kPa}Vballoons=4LV_{\text{balloons}} = 4 \, \text{L}Pballoons=150kPaP_{\text{balloons}} = 150 \, \text{kPa}Nballoons=?N_{\text{balloons}} = ?


According to the Boyle's law (isothermal process)

VbottlePbottle=PballoonsVtotalV_{\text{bottle}} P_{\text{bottle}} = P_{\text{balloons}} V_{\text{total}} were VtotalV_{\text{total}} is the total volume of the helium after inflating balloons. Such as after inflating the balloons in bottle is the helium too


Vtotal=NballoonsVballoons+VbottleV_{\text{total}} = N_{\text{balloons}} V_{\text{balloons}} + V_{\text{bottle}}VbottlePbottle=Pballoons(NballoonsVballoons+Vbottle)V_{\text{bottle}} P_{\text{bottle}} = P_{\text{balloons}} (N_{\text{balloons}} V_{\text{balloons}} + V_{\text{bottle}})Nballoons=VbottlePbottlePballoonsVbottleVballoonsN_{\text{balloons}} = \frac{\frac{V_{\text{bottle}} P_{\text{bottle}}}{P_{\text{balloons}}} V_{\text{bottle}}}{V_{\text{balloons}}}Nballoons=451000150454=63.75N_{\text{balloons}} = \frac{\frac{45 \cdot 1000}{150} \cdot 45}{4} = 63.75


Such as the number of the balloons must be integer

Answer: 63 balloons.

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