Answer to Question #343819 in Molecular Physics | Thermodynamics for kate

Question #343819

A boy throws a baseball onto a roof and it rolls back down and off the roof with a speed of 3.80 m/s. If the roof is pitched at 24.0° below the horizon and the roof edge is 3.30 m above the ground, find the time the baseball spends in the air and the horizontal distance from the roof edge to the point where the baseball lands on the ground.


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Expert's answer
2022-05-22T14:37:16-0400
y=y0v0sinθtgt2/2y=3.301.55t4.9t2y=y_0-v_0\sin\theta t-gt^2/2\\ y=3.30-1.55 t-4.9t^2

At the grounf level

y=03.301.55t4.9t2=0y=0\\ 3.30-1.55 t-4.9t^2=0

The time of flight

t=0.678st=0.678\:\rm s

The horizontal distance

R=v0cosθt=3.80cos24.00.678=2.35mR=v_0\cos\theta t\\ =3.80\cos 24.0^\circ*0.678=2.35\:\rm m


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