Question

A scuba driver is in fresh water has a tank with a volume of 0.0100m^3. The air in the tank is initially at a pressure of 1.00×10^7 Pa. Assume that the driver breathes 0.500 L/s of air. Density of fresh water is 1.00×10^3 kg/m^3.

How long will it take the tank at depths of 2.70 m?

Answer 1

$V_2=V_1\frac{p_1}{p_0+\rho gh}=0.78~m^3,$

$t=\frac Vv=26~min.$