Question #342408

At 0.0°C and 1.00 atm, 1.00 mol of a gas occupies a volume of 0.0224 m3.

 What is the number density?


1
Expert's answer
2022-05-18T15:28:18-0400
P=nkTP=nkT

n=PkT=101.31031.381023273=2.71025m3n=\frac{P}{kT}=\frac{101.3*10^3}{1.38*10^{-23}*273}=2.7*10^{25}\:\rm m^{-3}


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS