At 0.0°C and 1.00 atm, 1.00 mol of a gas occupies a volume of 0.0224 m3.
Estimate the average distance between the molecules.
pV=mMRT, ⟹ pV=\frac mM RT,\impliespV=MmRT,⟹
m=MpVRT=14.01 g.m=\frac{MpV}{RT}=14.01~g.m=RTMpV=14.01 g.
ρ=mV=0.625 kgm3.\rho=\frac mV=0.625~\frac{kg}{m^3}.ρ=Vm=0.625 m3kg.
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