What will be the change in internal energy of a system that absorbs 300 J of heat and performs 500 J of work?
Calculate the change in internal energy, 400 J of work is done on the system and the system losses 225 J of heat energy.
1) ΔE=Q+W=300 J−500 J=−200 J\Delta E=Q+W=300\ J -500\ J=-200\ JΔE=Q+W=300 J−500 J=−200 J
2) ΔE=Q+W=−225 J+400 J=175 J\Delta E=Q+W=-225\ J+400\ J=175\ JΔE=Q+W=−225 J+400 J=175 J
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