What is the amount of heat required to raise the temperature of 2 moles of mono atomic gas under isobaric condition form 0 to 100 degree centigrade?
Solution:
We have ν=2 mol ΔT=100 K
Need to find Q.
Let Q – the heat required to raise temperature from 273K to 373 K
A – work which makes gas
ΔU – increase in the internal energy of the gas
So Q=A+ΔU
In isobaric variant we have: A=pΔV=νRΔT
for mono atomic gas -> ΔU=23νRΔT
So Q=νRΔT+23νRΔT=25νRΔT=25⋅2⋅8.31⋅100=4155 J
Answer: 4155 J