A spacecraft antenna is at an angle of 10◦
relative to the axis of the spacecraft. If the
spacecraft moves away from the earth at a speed of 0.70c, what is the angle of the antenna
as seen from the earth?
θ′=arctantanθ1−v2c2=14°.\theta'=\arctan{\frac{\tan\theta}{\sqrt{1-\frac{v^2}{c^2}}}}=14°.θ′=arctan1−c2v2tanθ=14°.
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