A piece of copper 700g is heated to100°c and then quickly transferred to a copper calorimeter of mass 20g containing 500g of liquid of unknown specific heat capacity of liquid calculate the specific heat capacity of copper 3900j/kg
c1m1(100−50)=c1m2(50−20)+cm3(50−20),c_1m_1(100-50)=c_1m_2(50-20)+cm_3(50-20),c1m1(100−50)=c1m2(50−20)+cm3(50−20),
c=2500 Jkg⋅°C.c=2500~\frac J{kg\cdot °C}.c=2500 kg⋅°CJ.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments