The temperature of 200 g of water decreases from 20 °C to 0 °C in 10 minutes. Calculate
i. the heat lost by the water.
ii. the rate at which the water is losing heat.
iii. the time taken for the water at 0 °C to turn completely into ice.
1.
Q=cm∆T=16.8 kJ,Q=cm∆T=16.8~kJ,Q=cm∆T=16.8 kJ,
2.
Q˙=Qt=28 Js,\dot Q=\frac Qt=28~\frac Js,Q˙=tQ=28 sJ,
3.
Q1=cm∆T+λm=83.6 kJ,Q_1=cm∆T+\lambda m=83.6~kJ,Q1=cm∆T+λm=83.6 kJ,
t1=Q1Q˙=49.8 min.t_1=\frac{Q_1}{\dot Q}=49.8~\text{min}.t1=Q˙Q1=49.8 min.
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