Find the change in entropy when 1.25 kg of steam at 100°C condenses and cools to 50°C.
Q=m(L+c(100−50))=3.14 MJ,Q=m(L+c(100-50))=3.14~MJ,Q=m(L+c(100−50))=3.14 MJ,
∆S=Q∆T=63 kJK.∆S=\frac Q{∆T}=63~\frac{kJ}K.∆S=∆TQ=63 KkJ.
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