Find the change in entropy when 1.25 kg of steam at 100°C condenses and cools to 50°C.
"Q=m(L+c(100-50))=3.14~MJ,"
"\u2206S=\\frac Q{\u2206T}=63~\\frac{kJ}K."
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment