A 3.00-µF and 4.00-µF capacitor are connected in series, and this combination is connected in parallel with a 2.00-µF capacitor. (a) Show the illustration (b) What is the net capacitance?
Solution;
The two in series;
"\\frac{1}{R_T}=\\frac 13+\\frac14=\\frac{7}{12}"
"R_T=\\frac{12}{7}u F"
They are then connected in parallel with 2uF;
"R_{net}=\\frac{12}{7}+2=3.174uF"
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