1 kg of steam at 100 bar and 370℃ expands reversibly in a perfectly thermally insulated cylinder behind a piston until the pressure is 38 bar and the steam is then dry saturated. Calculate the work done
U=H−PVU=H-PVU=H−PV
U1=2998.82−100∗0.002416∗105103=2757.22(KJ/kg)U_1=2998.82-\frac{100*0.002416*10^5}{10^3}=2757.22 (KJ/kg)U1=2998.82−103100∗0.002416∗105=2757.22(KJ/kg)
Ug=2801.18−38∗0.0524672∗105103=2601.8(KJ/kg)U_g=2801.18-\frac{38*0.0524672*10^5}{10^3}=2601.8 (KJ/kg)Ug=2801.18−10338∗0.0524672∗105=2601.8(KJ/kg)
W=U1−U2=2757.22−2601.8=155.42(KJ/kg)W=U_1-U_2=2757.22-2601.8=155.42(KJ/kg)W=U1−U2=2757.22−2601.8=155.42(KJ/kg)
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