Answer to Question #319178 in Molecular Physics | Thermodynamics for Maryam

Question

1. A copper cube with sides of length 40mm had its surface blackened. The cube is heated up to 500K and place inside a room at a constant temperature of 300K. Calculate the initial rate of temperature fall of the cube, assuming it is a perfect blackbody. Take S.H.C of Aluminium to be 400J/kg/K, density of aluminium-7800kg/m'.

Answer 1

$\frac Q {\Delta t S}=\frac{c\rho V\Delta T}{\Delta tS}=\sigma (T_1^4-T_2^4),$

$\frac{\Delta T}{\Delta t}=\frac{6\sigma (T_1^4-T_2^4)}{c\rho a}=0 .15~\frac Ks.$