Question #317438

A body of mass 0.6kg is thrown vertically upward from ground with a speed of 20ms-1. Calculate its potential energy at the maximum height


1
Expert's answer
2022-03-24T16:18:58-0400

The potential energy at the maximum height is equal to the initial kinetic energy

Ep=mv022=0.62022=120JE_p=\frac{mv_0^2}{2}=\frac{0.6*20^2}{2}\\ =120\:\rm J


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